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Module 3 of 14 · 14 min

Dilution & concentration

Making a weaker solution from a stock — a mouthwash, a soak, a paediatric oral dilution, an IV admixture — is daily pharmacy work, and the exam tests whether you know the difference between the volume of DILUENT to add and the FINAL volume.

$$C_1V_1 = C_2V_2\qquad(\text{amount of drug before} = \text{amount after})$$

🧠 Drug in = drug out. V2 is the bottle you end with, not the water you pour.

Diluting adds solvent, never drug. The amount of drug, $Q = C\times V$, is the same before and after, which gives $C_1V_1 = C_2V_2$. Any matching units work (% with mL, mg/mL with mL, % w/w with g) as long as both sides use the same ones.

$V_2$ is the FINAL volume, not the volume of water you add. Diluent to add $= V_2 - V_1$ (assuming volumes are additive; for alcohol–water mixtures make up 'qs to volume' because they shrink on mixing).

'Dilute 1 in 20' means 1 part of stock in 20 parts TOTAL (1 + 19 diluent), so the concentration falls by a factor of 20. In a serial dilution, the factors multiply: a 1-in-10 followed by a 1-in-10 is a 1-in-100 overall.

A trituration is a dilution of a potent powder with an inert one (usually lactose) so a tiny dose can be weighed accurately. A 1:20 trituration contains 1 g of drug in every 20 g of mixture — so you weigh 20× the drug amount you need.

🧭 The method

  1. 1Put both strengths in the same units (convert ratio strength to %, mg/mL to %, etc.).
  2. 2Write C1V1 = C2V2 and label which side is the stock and which is the product.
  3. 3Solve for the unknown (usually the stock volume V1).
  4. 4If asked how much diluent, subtract: V2 − V1.
  5. 5Check: the product must be weaker than the stock and its volume larger.