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Module 4 of 14 · 12 min

Alligation

Whenever you mix two strengths of the same thing — two creams, two dextrose bags, alcohol of two strengths, or a cream plus pure powder — alligation gives the proportions in one quick grid. It is a favourite compounding question on both exams.

$$\text{parts of stronger} = d - L\qquad\text{parts of weaker} = H - d\qquad(L < d < H)$$

🧠 Cross the diagonals: each ingredient's parts come from the OTHER corner. Closer to d → more of it.

Alligation alternate answers 'how much of each?' when you mix a stronger (H) and a weaker (L) preparation to get a desired strength (d). Draw a grid: H top-left, L bottom-left, d in the middle. Subtract along the diagonals (ignore signs): the stronger gets $d - L$ parts, the weaker gets $H - d$ parts.

Pure drug counts as 100%; a base, water or petrolatum with no drug counts as 0%. If one ingredient's amount is already fixed (e.g. 'add to 90 g of 2% ointment'), match that amount to its parts and scale the other — don't scale against the total.

Alligation medial answers the opposite question: 'what strength do I get?' Weighted average: $\%_{\text{final}} = \frac{\sum(\text{amount}\times\%)}{\sum\text{amount}}$.

When one of the two components is 0% (pure diluent), alligation and $C_1V_1 = C_2V_2$ give the same answer — use whichever is quicker. Alligation is genuinely needed when BOTH components contain drug.

🧭 The method

  1. 1Check the desired strength lies between the two you have (otherwise it can't be made).
  2. 2Grid: H and L on the left, d in the centre; parts of H = d − L, parts of L = H − d.
  3. 3Total parts = sum. If the total amount is given: each amount = total × (its parts / total parts).
  4. 4If one component's amount is fixed instead: amount of other = fixed amount × (other parts / fixed parts).
  5. 5Check with alligation medial: the mixture's % should come back to d.